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How many individuals should I screen to be 95% confident of recovering the favorable genotype at a certain number of loci?

Discover how to calculate the number of plants needed to recover target genotypes in marker-assisted selection, and align your breeding strategy with available resources.

When planning a cross for marker-assisted selection, this question is often overlooked.Yet a simple calculation can help breeders determine whether their genotyping resources and nursery capacity are sufficient to screen enough plants to recover the desired genotype.

Here is how it works:
๐ŸŽฏ Step 1: Define the genetic target
Before calculating probabilities, we must clear our genetic context because genotype frequencies depend on:
โ€ข the crossing scheme (selfing vs. backcrossing)
โ€ข the generation where screening is performed
โ€ข the number of loci involved
โ€ข the loci being or no independent

For example, suppose:
โ€ข Two inbred parents are crossed
โ€ข The Fโ‚ is selfed to produce an Fโ‚‚ population
โ€ข We want plants carrying favorable alleles at 3 independent loci
If we require homozygous favorable genotypes, segregation in Fโ‚‚ is:
AA : Aa : aa = 1 : 2 : 1
The probability of obtaining a homozygous favorable genotype (AA) at one locus is:
P = 1/4
For 3 independent loci:
P(desired genotype) = (1/4)ยณ = 1/64
So the probability that one Fโ‚‚ plant has the full genotype is:
p = 1/64 = 0.0156

๐ŸŽฏ Step 2: Calculate how many plants must be screened
To be 95% confident of recovering at least one desired individual, the population size can be estimated using the formula:
N = ln(1 โˆ’ 0.95) / ln(1 โˆ’ p)
With p = 1/64:
N โ‰ˆ 190
๐Ÿ‘‰ About 190 Fโ‚‚ plants must be screened to have a 95% probability of recovering one individual homozygous for the favorable allele at the three loci.
๐Ÿ“Œ Practical note:
In real breeding programs, some data points are usually lost due to sampling errors, DNA extraction issues, or PCR failures.
For this reason, it is advisable to add about 10% more plants to the calculated number to compensate for potential genotyping losses.

๐Ÿ’ก A practical shortcut: selecting carriers
In many breeding programs, it is not necessary to select fully homozygous individuals in the Fโ‚‚ generation.
If heterozygous plants carrying the favorable allele are also accepted, these genotypes occur more frequently than homozygous ones. As a result, the probability of recovering the desired allele combination increases and the number of plants that must be screened can be substantially reduced.

๐Ÿš€ Before starting a marker-assisted selection strategy, ask:
โ€ข How many loci am I pyramiding?
โ€ข Do I need homozygous individuals or just allele carriers (heterozygotes)?
โ€ข What is the probability of recovering the genotype?
โ€ข Does my nursery and genotyping capacity match this probability?


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By Rachil Koumproglou